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Practice Solving Algebra Equations – with Video Solutions

Staring at a blank screen or a notebook full of scribbled equations here in Canada can make you feel like everyone else got handed a secret decoder ring while you were looking the other way. If you are sitting at your kitchen table trying to brush up on basic algebra practice questions Canada-wide for an upcoming trade assessment, apprenticeship exam, or academic entrance test, take a deep breath. You aren’t bad at math; you’ve just been handed textbooks that treat numbers like a foreign language instead of a practical tool.

The single biggest roadblock standing in your way is understanding variables and abstract thinkingβ€”that jarring moment when numbers suddenly turn into letters and you’re expected to treat an unknown like an active participant. Traditional classrooms love to rush you through this, but here at Complete Test Preparation Inc. in Victoria, we do things differently. With our AI Study Hall Tutor and step-by-step guidance, you can clear up the confusion and pass your test on the very first try.

Career Roadmap

Let’s talk about what happens when you let a single math prerequisite block your momentum. Imagine you are aiming to secure your certification, step into a skilled trade, or advance your career across the provinces. The path usually looks straightforward on paper: you spot the target exam, register with your provincial regulatory or educational body, submit your paperwork, and prepare to test.

Then you hit the hidden hurdle: the math screening section. Suddenly, you’re faced with multi-step algebraic word problems and equations with variables on both sides. If you stumble here, it triggers a domino effectβ€”retake waiting periods, delayed certifications, paused job applications, and months of suspended life where your career goals stay parked while you shell out more money for another test fee. That’s why getting ahead of these concepts now matters so much.

Two stages: a timed challenge, then practice on the rest.

    Ready to stop studying for a generic test that doesn’t fit your life?

    Our full Basic Algebra Online Course gives you hundreds of job-site relevant practice questions, clear tutorials, and lifetime access for just $19.99 CAD.

    Basic AlgebraΒ  Β —Β  Β  Advanced Algebra

    What’s Really Tripping People Up

    Why Understanding Variables and Abstract Thinking Feels Like a Trap

    When arithmetic turns into algebra, smart people freeze up because they are looking for a rigid, single-number answer where flexible thinking is required. As researchers note, “Variables are the core of algebra, and understanding of their nature and behavior is critical to students’ success.” (Emerald Publishing, Research on Variables and Expressions).
    Students often treat variables as unknown numbers rather than placeholders for quantities, leading to fundamental misunderstandings. Let’s break down the exact language and hurdles that cause test-takers to stumble.

    Solving equations with variables on both sides

    When an equation throws x terms on the left and the right (like 2x + 3 = x + 7), logic locks up because traditional arithmetic taught you to combine everything in sight. Balancing both sides requires a mental shift that school textbooks rarely explain in plain English.

    Algebra sign errors and negative numbers

    “Sign Errors. This one tops the list of common algebra mistakes.” (Mathnasium, 5 Most Common Algebra Test Mistakes). Distributing a negative sign across parentheses or multiplying two negative numbers remains one of the easiest ways to bleed points on a test without even realizing it.

    Translating word problems into algebra

    “The hardest thing about doing word problems is using the part where you need to take the English words and translate them into mathematics.” (Purplemath, Translating Word Problems). Parsing complex paragraphs to find out what h or y actually represents requires linguistic decoding, not just raw calculation.

    The Anatomy of a Wrong Answer

    Consider a classic test trap: solving 5x + 3 = 7x – 1.
    A stressed student looks at the 5x and 7x, both have a ‘x’ so moves the 7x over and gets
    5x + 7x + 3 = -1
    then simplifies for
    12x = 2
    x = 6
    spot the error? Where did this go wrong?
    Moving a term across the equals sign is like crossing a borderβ€”its sign has to flip from positive to negative (or vice versa). Treat the equals sign like a tightrope balance beam: whatever you do to one side, you must do to the other to keep things level.
    the correct solution is :
    5x + 3 = 7x – 1

    5x – 7x + 3 = -1

    -2x = -1 – (-3)

    -2x = -4Β  Β so x = 2

    Common Mistakes Answering Linear Equation Questions

    1. Misinterpreting the Question orΒ Β Setting Up the EquationΒ Incorrectly
      • Failing to properly understand what the question is asking.
      • Confusing linear equations with other types of algebra.
      • Misreading the problem and setting up the wrong equation.
    1. Β Basic Arithmetic Errors
    2. Solving for the Wrong Variable:
      • Solving for the wrong variable.
    3. Sign Errors:
      • Incorrectly using positive and negative signs.
      • Failing to change the sign when performing basic operations.
    4. Fractions and Decimals:
    5. Incorrect Distribution
      • Mistakes when applying the distributive property.
      • Forgetting to distribute a negative sign through parentheses.
    6. Incorrectly Combining Like TermsΒ 
      • Failing to properly combine like terms.
      • Mistaking terms that are not alike for like terms.
    7. Skipping Steps:
      • Skipping steps in the process, leading to errors in the solution.
      • Not showing work, making it hard to identify where a mistake was made.
    8. Checking Solutions:
      • Forgetting to plug the solution back into the original equation to check its correctness.
      • Assuming an answer is correct without verification.
    9. Mistakes Graphing
      • Errors plotting or connecting points.
      • Misinterpreting the slope and intercept in the line equation.
    10. Time Management:
      • Spending too much time on one problem and rushing through others.
      • Not allocating enough time to review and check answers.Β  Time Management on a Test
    11. Anxiety and Pressure:
      • Feeling overwhelmed or stressed causing incorrect answers.
      • Making careless mistakes due to test anxiety.Β  Test Anxiety Tips

     

    Algebra Solution Video Walk Through

    5x + 3 = 7x – 1. Find x

    a. 1/3
    b. Β½
    c. 1
    d. 2

    Answer: D

    5x + 3 = 7x – 1
    first we need to collect like terms second is to undo addition and subtraction third and the last is to undo multiplication and division so again the first step is to put 5x and 7x in one side = 7x-5x
    second put 3 and 1 in one side = 7x – 5x = 3 + 1
    now we will solve the answer = 2x = 4
    now we will divide by 2 to the both sides 2x/2 = 4/2
    the answer now is x = 2

    1. Video Solution

    Tips From Students

    Tip 1: The “Line-by-Line” Rule. Write everything down, even if it feels tedious.

    “Stop trying to be a hero in your head. Write out every single micro-step, especially when negative signs are involved. It slows you down for ten seconds but saves you ten minutes of hunting for your mistake.”

    Tip 2: Check Your Work with Reverse Substitution. Plug your answer back into the original equation immediately.

    “Before you move on, take five seconds to plug your number back in. If the left side doesn’t equal the right side, you know right away instead of finding out at the very end of the test.”

    Tip 3: Translate Words to Math First. Circle the verbs and unknowns before touching the numbers.

    “When I see a word problem, I underline the ‘is’ (equals), the ‘more than’ (plus), and the unknown. Once I translate the English into plain math, the algebra part is easy.”

    Try a FREE Algebra Quiz

    Master Basic Algebra for Your Canadian Career Entrance Exam

    Learn algebra for $19.99β€”lifetime access, no subscription, no hidden fees

    Basic AlgebraΒ  Β —Β  Β  Advanced Algebra

    Frequently Asked Questions

    Why is algebra so tricky, and how can I actually get better at it? Most of the time, math feels hard because textbooks skip the tiny steps in the middle. The secret is breaking problems down into bite-sized patterns and practicing just a few minutes a day instead of cramming for three hours on a Sunday night.
    Are these practice questions really free? Yep, absolutely. You can use the free 2-minute challenges and practice problems right here on the page as much as you need to sharpen your skills. No hidden traps or sudden paywalls.
    What if I need help with more than just basic algebra? If you find yourself wanting a full, step-by-step roadmap from basic equations all the way to word problems and graphing, take a look at the complete online course. It’s built to walk you through the whole subject without the confusing jargon.
    Can parents or teachers use these resources for their students? Of course! Whether you’re homeschooling, tutoring at the kitchen table, or teaching a classroom, you’re welcome to use these practice tools. We believe in keeping things straightforward and accessible for everyone who wants to learn.Β  See also out content licensing options
    Updated: Monday, October 26th, 2026
    Published: Thursday, October 11th, 2012

    Our Independent Publishing Standards β€” Built by Educators

    Every algebra practice question and 2-minute drill on this page is written, reviewed by experienced math teachers. For 20 years, Complete Test Preparation Inc. has avoided generic, imported question banks and focused on practice that helps students build real confidenceβ€”without unnecessary stress.

    Independent & Local: No corporate call centers or fillerβ€”just clear, practical guidance from educators who understand where algebra students get stuck.

    Giving Back: A portion of every book and course sale supports educational charities and children’s literacy programs.

    β€” Brian Stocker, M.A., Complete Test Preparation Inc.

      36 Comments

    1. Timothy Crouse
      January 21, 2014 1:24 pm
      Reply

      I need to know how to do the formula in order to pass algebra to get accepted into a practical nursing program. Also, I need to learn basic mathematics.

    2. James R.
      September 7, 2015 9:42 pm
      Reply

      you can search the formulas for basic allgebra online

    3. Helpful Person
      February 4, 2017 3:34 pm
      Reply

      In order to solve it you have to look at the two sides separated by the equal sign then combine like terms after you add or subtract from both sides so a variable(s) is on one side and the numbers are on one side then if they have a common factor divide them by the smallest of the two then you will get your answer.

    4. alana
      August 6, 2019 2:53 pm
      Reply

      Hello Will you please show me how you break this problem down in order to solve it. I read what you wrote and it makes sense but i’m visual and need to see it broken down as well as explained.
      1. 5x + 3 = 7x – 1. Find x
      is it 8x = 6x
      4x divided by 3x x = .3333 or 1/3
      haha! help. thanks.

      a. 1/3
      b. Β½
      c. 1
      d. 2

    5. cal
      October 27, 2019 3:35 am
      Reply

      5x+3=7x-1
      subtract the 5x from 7x to move it to the other side to make equation 3=2x-1
      now add the 1 to the 3 to move it to the other side to make the equation 4=2x
      now subtract the 2 from the x to isolate the x and make the equation 4/2=x
      4/2=2
      X=2

    6. Abigale kirsten
      October 27, 2019 3:43 am
      Reply

      No, You cannot add and subtract number just because they are next to each other. You must align same groups with each other.
      5x needs ti be joined with 7x, +3 needs to be joined with -1.
      However, when we align and group them, it means switching them from theyre placements where they will cross the equal sign.
      The rule is, anything that has to cross the equal sign in order to group numbers will automatically have their plus and minus signs changed.
      Therefore, this is how itll look.

      5x + 3 = 7x – 1. Find X,
      5x – 7x = – 1- 3
      -2x = + 4
      x = +4 / +2
      x = +6

      Note: 5x – 7x became -2x, as 7 is the bigger number out of the two that are being subtracted, therefore the result will adopt the minus sign from the bigger number.
      Note: -1 -3 became +4 because whenever you put minus and minus together, they become a positive. Those are the rules of Algebra,

    7. Mehmet Yilmaz
      December 20, 2019 2:47 pm

      Sorry Abigale Kirsten, but that isn’t correct, -1-3 isn’t equal to +4, because that only happens in multiplication, what will happen here is it will equal -4 because -1-1 is equal to -2, if anyone disagrees please check it via a calculator.
      Coming to the question, 5x + 3 = 7x – 1. Find X
      We take -1 to the other side making it positive
      5x+3+1=7x
      This equals to
      5x+4=7x
      Here we now take 5x to the other side
      4=7x-5x
      which equals to
      4=2x
      we divide both sides by 2
      And the answer is
      x=2

      I anyone doubts this please use google or a specialized calculator to check it.

    8. Brian Stocker
      December 20, 2019 3:46 pm

      thanks for the great explanation – better than mine!

    9. wee
      February 29, 2020 3:44 am

      Im in 7th grade and I finished this problem in 20 sec and the answer is x = 2. step by step is 5x+3=7x-1 —> you minus 5x on both sides because it is the smaller variable and you get 3 = 2x-1. The opposite of subtraction is addition, we need to isolate the x variable by getting rid of the -1 so we do (-1) + 1 is 0 and we do it on both sides of the equal sign. then the equation would be 3 + 1 = 2x -1 +1. After that, the equation would look like this: 4 = 2x then we divide the variable on both sides so it would be 4/2 = 2/2, —> then 2=x

    10. Anonymous
      January 25, 2022 2:05 am
      Reply

      5x + 3 = 7x – 1
      1st step: minus 5x from both sides
      3 = 2x + 1
      2nd step: add 1 to both sides
      4 = 2x
      3rd step: divide both sides by 2
      2 = x

    11. Sultan
      March 9, 2020 5:53 am
      Reply

      Wow this is good plus who can solve this
      7(x+4)-2[x-3(5+x)]=2/3(x-6)
      a. 6
      b.7
      c.-6
      d.3

    12. Anonymous
      October 3, 2020 10:03 am
      Reply

      is it c

    13. Stephen _ osele - math _ ox
      June 14, 2021 5:23 pm
      Reply

      Awooden block has a volume of 90cubic centimetre.find the volume of the block formed by enlarging the block with a linear scale factor of 4.

    14. Sandra
      January 24, 2017 3:04 pm
      Reply

      Could you explain 4 like you did 1?

    15. Brian
      January 24, 2017 7:43 pm
      Reply

      OK updated solution for #4 – will get to the others soon!

    16. Anonymous
      February 8, 2022 2:23 am
      Reply

      Thanks Brain, really like that you explained the questions. Really help me.

    17. Tammy kent
      March 23, 2017 1:56 am
      Reply

      for question 2. I keep getting 2 for an answer. Can you please show the breakdown on the solution.

    18. Brian
      March 23, 2017 4:01 pm
      Reply

      ok!

    19. Odey Grace
      June 1, 2017 6:42 pm
      Reply

      Please no I need explanation for no 7

    20. Sunny
      June 4, 2018 7:53 am
      Reply

      150 Γ— .30 = 45 + 150 = 195

    21. Regis Finn
      June 30, 2020 5:30 pm
      Reply

      Or to make it easier, multiple by 1.30 instead of .30

    22. Tahmina Hossain
      February 8, 2018 11:34 pm
      Reply

      Answer for question 5 should be c. 20%

    23. Brian
      February 9, 2018 6:32 pm
      Reply

      The price increased from $20 to $25 ($5) so the question is 5 is what percent of 20.Β  Or, 5/20 = x/100Β  ;Β  500/20 = 25%

    24. leilei
      March 7, 2019 10:42 pm
      Reply

      THIS IS TOOOOOOO HARD IM NEVER DOING ALGEBRA AGAIN BUT I DID GET THE CORRECT ANSWER THO

    25. chris
      June 29, 2019 4:28 pm
      Reply

      or x/150=1.3 because a 30% increase is really 130% or 1.3 so if you start with x/150=1.3 you solve for x by multiplying 150 and 1.3 so the equations becomes 150*1.3=x so solving for x X=195

    26. Julie
      August 18, 2023 5:50 pm
      Reply

      lol fr I am done high school and some of it is hard for me…. πŸ™

    27. leslee smith
      April 30, 2020 7:17 pm
      Reply

      can you please show me how to breakdown and solve number 11?

    28. Ashu
      July 1, 2020 5:40 am
      Reply

      Can u do other questions around square and cubing digits and dividing and multiplying using algebraic equations

    29. Sarah
      September 21, 2020 4:19 am
      Reply

      There are a number of 7L tins of paint and 5L tins of paint. How many tins of each do we need to make up 102L of paint?
      How is this worked out in an algebra equation?

    30. Jeremy
      September 25, 2021 4:06 am
      Reply

      Love the questions, I just wanted to know why question 11 is 3/7 and not -1/7? Every time I plug 3/7 back into the equation I don’t get 4. Please explain this to me. Thank you

    31. Muhamad Auff
      December 2, 2021 9:15 pm
      Reply

      #8 can you verify this should be 18?

      x+2×3=24
      x+6=24
      x=18

    32. Brian Stocker
      December 2, 2021 9:59 pm
      Reply

      Hi – no the solution is correct – you have missed the brackets – it is 3(x + 2) which is different to x + 2 X 3 – I have added some additional steps and explanations to the answer key.

    33. Anonymous
      January 5, 2022 12:59 am
      Reply

      marc has 3 times more mass than his sister. His sister has a mass of 16 kg. what is marc’s mass?

    34. Anonymous
      February 24, 2022 10:35 am
      Reply

      derive an equation towards the statement
      let marc’s mass be x
      sister is 16kgs
      we’re told marc is 3 times more than sister in terms of mass
      therefore;
      marc = xkgs=3(16)
      hence x=3×16 :=48kgs

    35. June 28, 2022 4:29 pm
      Reply

      i do not understand no.5 πŸ™ why does it say “5 is what percent of 20” i don’t get it πŸ™

    36. March 3, 2023 5:14 pm
      Reply

      Ok – the original price was $20 and it increased by $5 to the new price – $25

      Original Price – $20
      Increase in Price – $5
      New Price – $25

      To find the % increase in price –

      The question becomes – Increase in Price ($5) is what percent of the Original Price ($20)

      So, 5 is what percent of 20.

      Or, 5/20 = x/100 ; Convert to Percent

      (5/20) * 100 = (x/100) * 100 Multiply both sides of the equation by 100 to simplify

      500/20 = 100/100

      500/20 = 1

      500/20 = 25%

      Do NOT take the % of the New Price! The question asks how much did the price increase, so use the Original Price!

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